Question

∠X=5x+30
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​ \angle \mathrm{Y}=3\mathrm{x}+60^{\circ}∠Y=3x+60
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Answer 1

Corresponding angles on parallel lines cut by a transversal are equal

5x + 30 = 3x + 60

Subtract 3x from both sides

2x + 30 = 60

Subtract 30 from both sides

2x = 30

Divide both sides by 2

X = 15