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The length of a rectangle is 3 m less than double the width, and the area of the rectangle is 44 m. Find the dimensions of the rectangle

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Answer:

Length of Rectangle is 3 cm less than twice the width

Area is 44 m2 ; let W = width; 2W - 3 = Length

Arect = L times W

44 = W ( 2W - 3 )

44 = 2W2 - 3W

0 = 2W2 - 3W - 44

Factoring

0 = ( 2W - 11 )( W +4)

2W - 11 =0 ; W + 4 = 0

W = 11/2 W = -4 (width can not be a negative number)

Therefor: width is 11/2 and length is 8

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