Question

I NEED THIS ASAP!!! A ball is thrown straight up with an initial velocity of 4.40 m/s. Assuming there is no air friction, what is the maximum height the ball will reach? 40pts pls

Answer 1

I think it is 80m/s

Step-by-step explanation:

d = ½ g t2

= ½ (10 m/s2) (4 s)2

= (5 m/s2) (16 s2)

= 80 ms

75% sure

Hope this helps!!!