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B) Three two-digit integers have a mean average of 16 and a range of 16. The median of the integers is 12. If all three integers are even and all are different to each other, what are the 3 numbers?

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Answer:

The three numbers are 10,12 and 26

Explanation:

For the average of the numbers to be 16; it means that the sum of all the numbers will be:

3 * 16 = 48

If the median is 12, it means the middle number is 12

For the range to be 16, the difference between the highest and smallest number is 16

if the lowest is x, then the highest will be (x + 16)

So, if we added these and 12, we get 48

Thus;

(x + 16) + x + 12 = 48

2x + 28 = 48

2x = 48-28

2x = 20

x = 20/2

x = 10

Then, the last number will be x + 16 = 10 + 16 = 26

So, the three numbers are 10,12 and 26

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