Question

According to the eScience Lab Manual for Lab 1, Experiment 3, you need to prepare 65 ml of 60% soda/syrup prescription. To do this you can use the 80% soda solution and the syrup solution (0% strength) that you have in inventory. How many mls of soda solution do you need to create this final solution?

Answer 1

16.25 mL

Explanation:

Since we are mixing from the syrup in the inventory, we can say that the syrup in the inventory must be equal to that in the final solution. Thus, we will use the dilution equation to solve for the Initial volume;

Dilution equation is;

V₁C₁ = V₂C₂

Where;

V₁ is initial volume

C₁ is initial concentration or initial molarity

V₂ is final volume

C₂ is final concentration of final molarity

We are given;

C₁ = 80% = 0.8

C₂ = 60% = 0.6

V₂ = 65 mL

Making V₁ the subject in the dilution equation, we have;

V₁ = (V₂C₂)/C₁

V₁ = (65 × 0.6)/0.8

V₁ = 48.75 mL of inventory syrup

Since we have 48.75 mL of inventory syrup and the dilute solution is 65 ml, then the volume of soda solution required = 65mL - 48.75 mL = 16.25 mL