Question

Find a line that is perpendicular to y = 2/5x-1 that goes through (3,6)

Answer 1

To find a line perpendicular to the original line, we must set the new slope as the negative reciprocal of the original slope, 2/5.

So the slope of the perpendicular line is -5/2

Now using the point slope form, we have the slope -5/2 and (3,6)

`y- 6 = (-5)/(2)(x-3)\\y-6 =(-5)/(2) x + (15)/(2) \\y = (-5)/(2) x + (15)/(2) + 6\\y= (-5)/(2) x + (15)/(2) + (12)/(2) \\y = (-5)/(2)x +(27)/(2)`

Hope that helps!