Question

Please help me❗️❗️

A ball thrown into the air is modeled by the
equation
h(t) = -t2 + 4t + 5. Where h represents
the height of the ball and t represents
time.


What is the starting height of the ball?
What is the time the ball reaches its
maximum height?
What is the maximum height?
When does the ball hit the ground?
How high is the ball 1 second into
flight?

Answer 1

Below in bold.

Explanation:

Starting height is when t = 0

It is 5 units.

To find the maximum height we convert the equation to vertex form:

h = -t^2 + 4t + 5

h = -(t^2 - 4t - 5)

= - [(t - 2)^2 - 9]

= -(t - 2)^2 + 9

From this we see that the ball reaches max height after 2.

Maximum height = -2^2 + 4(2) + 5

= 9 units.

Ball reaches the ground after 2*2 = 4 .