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The points (1, 4) and (–3, 2) are the endpoints of a diameter of a circle. What is the equation of the circle? A (x−1)2+(y+3)2=5–√ B (x+1)2+(y−3)2=5–√ C (x−1)2+(y+3)2 =5 D (x+1)2+(y−3)2=5
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The points (1, 4) and (–3, 2) are the endpoints of a diameter of a circle. What is the equation of the circle?

A (x−1)2+(y+3)2=5–√


B (x+1)2+(y−3)2=5–√


C (x−1)2+(y+3)2 =5


D (x+1)2+(y−3)2=5

User UnknownBeast
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1 Answer

3 votes
The answer will be C
Have a good day
User Jlcv
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