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The points (1, 4) and (–3, 2) are the endpoints of a diameter of a circle. What is the equation of the circle? A (x−1)2+(y+3)2=5–√ B (x+1)2+(y−3)2=5–√ C (x−1)2+(y+3)2 =5 D (x+1)…
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The points (1, 4) and (–3, 2) are the endpoints of a diameter of a circle. What is the equation of the circle? A (x−1)2+(y+3)2=5–√ B (x+1)2+(y−3)2=5–√ C (x−1)2+(y+3)2 =5 D (x+1)…
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The points (1, 4) and (–3, 2) are the endpoints of a diameter of a circle. What is the equation of the circle?
A (x−1)2+(y+3)2=5–√
B (x+1)2+(y−3)2=5–√
C (x−1)2+(y+3)2 =5
D (x+1)2+(y−3)2=5
Mathematics
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UnknownBeast
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The answer will be C
Have a good day
Jlcv
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Feb 15, 2022
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Jlcv
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