Question

Given that sec(θ)=5/3 and θ is in Quadrant I, what is tan(θ)? Write your answer in exact form. Do not round.

Answer 1

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Answer:

tan(θ) = 4/3

Explanation:

The relationship between secant and tangent is ...

1 +tan² = sec²

The the tangent of the angle is ...

tan(θ) = √(sec²(θ) -1)

tan(θ) = √((5/3)² -1) = √(16/9)

tan(θ) = 4/3