Explanation:
Given equation is
2y = 3x + 10
3x - 2y + 10 = 0 .....i)
Any line parallel to line I) is
3x - 2y + k = 0 ......ii)
As the line two passes through the point ( 2 , - 5 ) Now substituting the values
3 * 2 - 2 * ( - 5) + k = 0
6 + 10 + k = 0
16 + k = 0
k = - 16
Now putting the value of k in equation two
3x - 2y + 16 = 0 is the required equation.
Hope it will help :)❤