Question

A force F is exerted at a distance D from the axis of rotation of a wrench and is exerted at an angle θ to the wrench (θ is the angle between the direction of the force and the wrench). What force f could be exerted on the wrench at a distance 2D and perpendicular to the wrench so that the torques created by the two forces are EQUAL. Give your answer in terms of F and θ.

Answer 1

Torque = R X F = R * F sin theta

-f * 2R will exert an equal opposite torque

-f * 2 = F sin theta

f = -F sin theta / 2