Question

For the reaction A(g)

* 2B(g) the
following concentrations where measured
at 25°C. The Kc for this temperature is 1
Is the reaction at equilibrium?
[A] = 4 M
[B] =2 M

Answer 1

Yes

Step-by-step explanation:

By definition, the equilibrium constanct, Kc, for the reaction A ⇒ 2B is

= [A]^1 / [B]^2

Substitute [A] = 4 and [B] = 2 in the equation,

[A]^1 / [B]^2

= 4^1 / 2^2

= 1

= Kc

So yes the reaction is at equilibrium.

Answer 2

Let's find K_c

`\\ \rm\Rrightarrow K_c=([B^]^2)/([A]^1)`

`\\ \rm\Rrightarrow 1=(2^2)/(4)`

`\\ \rm\Rrightarrow 1=(4)/(4)`

`\\ \rm\Rrightarrow 1=1`

Yes it's at equilibrium