Answer:
35.67 m/s
Step-by-step explanation:
Applying the formular for range,
R = u²sin2∅/g....................... Equation 1
Where R = Range, u = Initial Velocity, ∅ = angle of launch, g = acceleration due to gravity
make u the subject of the equation
u = √(Rg/sin2∅)............. Equation 2
Given: R = 122 m, g = 9.8 m/s², ∅ = 55°
Substitute these values into equation 2
u = √[(122×9.8)/(sin(2×55))]
u = √(1195.6/sin110)
u = √(1272.33)
u = 35.67 m/s