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In an NMR experiment, the RF source oscillates at 34 MHz and magnetic resonance of the hydrogen atoms in the sample being in- vestigated occurs when the external field Bext has magnitude 0.78 T. Assume that Bint and Bext are in the same direction and take the pro- ton magnetic moment component u, to be 1.41 X 10-26 J/T. What is the magnitude of Bint?

User Amazingjxq
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1 Answer

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Answer:


B_(int)=-0.015T

Step-by-step explanation:

From the question we are told that:

RF source oscillation speed
\sigma= 34 MHz

The external field
Bext =0.78 T.

Pro- ton magnetic moment component
\mu=1.41 X 10-26 J/T

Generally the equation for magnitude of
B_(int) is mathematically given by


B_(int)=B_(ext)-(h\triangle \sigma)/(2 \mu)


B_(int)=0.78-(6.6*10^(-34)*34*10^6)/(2*1.41*10^(26))


B_(int)=0.78-0.7957


B_(int)=-0.015T

User Zoran Pavlovic
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