Question

Need help with balancing chemical equations!

Answer 1

`\\ \rm\Rrightarrow 2Al(OH)_3+3H_2SO_4\longrightarrow Al_2(SO_4)_3+6H_2O`

on both sides

• Al=2
• OH=6
• SO_4=3

Hence balanced

Coefficient of H_2O is 6

Answer 2

`\qquad \qquad\huge \underline{\boxed{\sf Answer}}`

The balanced equation for given reaction is ~

`\sf 2 \: Al(OH)_3 +3 \: H_2SO_4 = Al_2(SO_4)_3 +6 H_2O`

And here, the Coefficient of H2O is 6