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3 votes
Evaluate intergral 10xe exponent 10x dx​

2 Answers

7 votes

Answer:

((10x-1)e^(10x))/10 + C

Explanation:

10 integral (xe^(10x)) dx

Integrate by parts f=x f'=1 / g'=e^(10x) g= (e^(10x))/10

(xe^(10x)/10) - integral (e^(10x)/10) dx

Solving integral (e^(10x)/10) dx :

1/100 integral (e^u) du

= e^u/1000 = e^(10x)/100

(xe^(10x)/10)-(e^(10x)/100)

10 integral (xe^(10x)) dx

= xe^(10x)- (e^(10x))/10

= xe^10x - (e^(10x))/10 + C

= ((10x-1)e^(10x))/10 + C

User Jace Rhea
by
5.1k points
6 votes

Answer:

for this type of question, integral by parts should be used . This involves using the formula for intregation by parts:

intudv=uv-intvdu.

lets first break apart the x and e10x into two parts - "u" and "v"

where u = x.

however, we need to find the value of v. in order to do this, we can integrate dv/dx in order to get to v.

the value of dv/dx is : e10x

u = x dv/dx = e10x

as seen in the formula, you need to have a value for u, dv, v and du.

therefore in order to get du you must differentiate u:

u = x

du/dx = 1

du = 1dx = dx

du = dx

in order to get v you need to integrate dv/dx:

\displaystyle \inte10x dx = 1/10 x10x

now that we have both parts, we can put this back into the formula.

intudv=uv-intvdu.

\displaystyle \intxe10x = x * 1/10e10x - \displaystyle \int1/10e10x dx

Explanation:

User Jonathanbell
by
4.4k points
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