Question

Evaluate the intergral2x(xsquared+3)exponent 4​

Answer 1

(x^2+3)^5/5 + C

Explanation:

Here substitute u = x^2 + 3 , du/dx = 2x ---> dx= 1/2x du

Then: integral (u^4) du

Apply power rule: u^5/5

Then replace the substitution u=x^2+3 in u

= (x^2+3)^5/5 + C