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A problem in mathematics is given to three students A, B and C whose chances of solving it are 1/3, 1/4 and 1/5 respectively. Find the probability that i. the problems will be solved? ii. the problems will not be solved?​

User Snowy
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1 Answer

4 votes

Answer:

i. 3/5

ii. 2/5

Step-by-step explanation:

Solving the problem by any of the students A, B and C is an independent event as solution by one does not restrict the other one from solving

However, the problem will be solved if even one of them solves the question

Now Probability of not solving the question by A, B and C are

PA (not solving a problem) - 1-1/3 = 2/3

PB (not solving a problem) - 1-1/4 = 3/4

PC (not solving a problem) - 1-1/5 = 4/5

ii) Probability of not solving - 2/3*3/4*4/5 = 2 *1/5 = 2/5

i) Probability of solving - 1- Probability of not solving

= 1 - 2/5 = 3/5

User AeroClassics
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