Question

Find the gradient of a normal line to the line 1.9y+-43.1x-{c}=0

Answer 1

The gradient of the normal line to the given equation is found by first expressing the original equation in slope-intercept form, determining its slope, and then taking the negative reciprocal of that slope. Thus, the gradient of the normal line is -1.9 / 43.1.

Step-by-step explanation:

To find the gradient of a normal line to the given linear equation 1.9y + -43.1x - {c} = 0, we first need to rewrite the equation in slope-intercept form (y = mx + b), where m represents the slope of the original line. To do this, solve for y:

1. Move the x-term to the other side: 1.9y = 43.1x + {c}.
2. Divide both sides by 1.9 to isolate y: y = (43.1 / 1.9)x + {c}/1.9.

The slope m of the original line is 43.1 / 1.9. A normal line is perpendicular to the original line, so its slope is the negative reciprocal of the original line's slope. Hence, the gradient of the normal line is -1.9 / 43.1.

Gradient of the normal line: -1.9 / 43.1

Answer 2

Here is the answer!!!!!!!