Question

The 1.5kg ball is launched straight upward with an initial velocity of 7m/s. What is the maximum height it will reach?​

Answer 1

h = 2.5 m

Step-by-step explanation:

Given that,

Mass of a ball, m = 1.5 kg

Initial velocity of the ball, u = 7 m/s

We need to find the maximum height reached by the ball. Let it is be h. Using the conservation of energy to find it such that,

`mgh=(1)/(2)mu^2\\\\h=(u^2)/(2g)`

Put all the values,

`h=(7^2)/(2* 9.8)\\\\=2.5\ m`

So, it will reach to a height of 2.5 m.