Question

What is the value of for this aqueous reaction at 298 K?

A+B↽⇀C+D ΔG°=12.86 kJ/mol

K=

Answer 1

The equilbrium constant is 179.6

Step-by-step explanation:

To solve this question we can use the equation:

ΔG = -RTlnK

Where ΔG is Gibbs free energy = 12.86kJ/mol

R is gas constant = 8.314x10⁻³kJ/molK

T is absolute temperature = 298K

And K is equilibrium constant.

Replacing:

12.86kJ/mol = -8.314x10⁻³kJ/molK*298K lnK

5.19 = lnK

e^5.19 = K

179.6 = K

The equilbrium constant is 179.6