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What is (14x^2– 27x+9) / (7x-3)?

A. 7x-3
B. 2x-3
C. -211x+9
D. 2x-33

2 Answers

2 votes

Answer:


\tt{}2x - 3

Explanation:


\tt{} \frac{(14 {x}^(2) - 27x + 9) }{(7x - 3)}


\tt{} \frac{14 {x}^(2) - 6x - 21x + 9 }{7x - 3}


\tt{} (2x * (7x - 3) - 3(7x - 3))/(7x - 3 )


\tt{}2x - 3

User Mcclosa
by
5.2k points
5 votes

Answer:

B. 2x - 3

Explanation:


\rm \frac{ {14x}^(2) - 27x + 9}{7x - 3}


\rm = \frac{ \cancel{(7x - 3)}(2x - 3)}{ \cancel{7x - 3}}


\boxed{ \rm \bold{= 2x - 3}}

User Roux Hass
by
4.7k points