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What is (3x^2+ 4x - 7) / (x - 1)?

A. 3x+1
B. X-1
C. 3x+7
D. 7x-7

1 Answer

2 votes

Answer:


\tt{}b. \: 3x + 7

Explanation:


\tt{} \frac{(3 {x}^(2) + 4x - 7) }{(x - 1)}


\tt{} \frac{{3x}^(2) + 7x - 3x - 7}{x - 1}


\tt{} (x * (3x + 7) - (3x + 7))/(x - 1)


\tt{} ((3x + 7) * (x - 1))/(x - 1)


\tt{}3x + 7

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