Question

A firework is launched with a force of 700 N and a momentum of 200 kg-m/s. How much time before is explodes?

Answer 1

t = 0.28 seconds

Step-by-step explanation:

Given that,

Force acting on a firework, F = 700 N

The momentum of the firework, p =200 kg-m/s

We need to find the time before it explodes. Ket the time be t. We know that, the rate of change of momentum is equal to external frce. So,

`F=(P)/(t)\\\\t=(P)/(F)\\\\t=(200)/(700)\\t=0.28\ s`

So, the required time is equal to 0.28 seconds.