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Find the product (x+3y^2) (3x-3y^2)

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Answer:

3x^2 - 12x·y^2 - 9y^2·y^4

Explanation:

Apply the distributive property of multiplication here.

x times (3x - 3y^2) is 3x^2 - 3x·y^2.

3y^2 times (3x - 3y^2) is 9x·y^2 - 9y^2·y^4.

Thus, the desired product of the given binomials is the sum of the above results:

3x^2 - 3x·y^2 - 9x·y^2 - 9y^2·y^4

which shortens to 3x^2 - 12x·y^2 - 9y^2·y^4

User Shandy
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