Answer:
![\boxed {\boxed {\sf 3.94 *10^(23) \ molecules \ C_6 H_ {14} }}}](https://img.qammunity.org/2022/formulas/chemistry/high-school/bj9wr9germn0t0heke1q6cw3niz8jmekod.png)
Step-by-step explanation:
1 mole of any substance has the same number of particles: 6.022 * 10²³. This number is as Avogadro's Number.
The particles can be molecules, atoms, formula units, etc. For this problem, the particles are molecules of C₆H₁₄ or hexane.
We can set up a ratio using Avogadro's Number.
![\frac {6.022 *10^(23) \ molecules \ C_6H_(14)}{1 \ mol \ C_6H_(14)}](https://img.qammunity.org/2022/formulas/chemistry/high-school/dke4hxi3wd89zedw69yl24nk4g7gfjyvlo.png)
Multiply by the given number of moles: 0.655
![0.655 \ mol \ C_6H_(14) * \frac {6.022 *10^(23) \ molecules \ C_6H_(14)}{1 \ mol \ C_6H_(14)}](https://img.qammunity.org/2022/formulas/chemistry/high-school/yf5cftjjof4ydm3fhcpgew8gs32dgtr2hd.png)
The moles of hexane will cancel, because one is the "numerator" (techincally 0.655 is over 1) and the other is in the denominator of the ratio.
![0.655 * \frac {6.022 *10^(23) \ molecules \ C_6H_(14)}{1 }](https://img.qammunity.org/2022/formulas/chemistry/high-school/uqobn0tzrs4hbhaphd1trqafvreslmklv1.png)
![0.655 * {6.022 *10^(23) \ molecules \ C_6H_(14)}](https://img.qammunity.org/2022/formulas/chemistry/high-school/yajqd7v1z60omcj26ukmtjpr24mjk8t3en.png)
![3.94441*10^(23) \ molecules C_6H_(14)](https://img.qammunity.org/2022/formulas/chemistry/high-school/wrb9i7i66ehflgxwoyncbtfv9zkyzmkosu.png)
The original value of moles has three significant figures, so our answer must have the same. For the number we found, that is the hundredth place.
The 4 in the thousandth place tells us to leave the 4 in the hundredth place.
![3.94 *10^(23) \ molecules \ C_6H_(14)](https://img.qammunity.org/2022/formulas/chemistry/high-school/tcq5zoy8hnykv2kbdvmsqxnecz7aguj1bt.png)
0.655 moles of hexane is equal to approximately 3.94 *10²³ molecules of hexane.