Question

Hernando and Rachel are factoring 2mp-6p+27-9m. Is either of them correct? Explain your reasoning,

Answer 1

See Explanation

Explanation:

The question is incomplete, as Hernando and Rachel's solution are not provided. So, I will just solve the question directly.

Given

`2mp-6p+27-9m`

Required

Factor

`2mp-6p+27-9m`

Group into 2

`2mp-6p+27-9m = [2mp-6p]+[27-9m]`

Factor each group

`2mp-6p+27-9m = 2p[m-3]+9[3-m]`

Rewrite 3 - m as -(m-3)

So, we have:

`2mp-6p+27-9m = 2p[m-3]-9[m-3]`

Factor out m - 3

`2mp-6p+27-9m = [2p-9][m-3]`