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You are in a 12-member panel. If two people from the panel are selected to represent the panel, what is the probability you

User Chamilyan
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This question is incomplete, the complete question is;

You are in a 12-member panel. If two people from the panel are selected to represent the panel, what is the probability you wont be selected.

[ Two decimal places ]

Answer:

The probability that you be selected is 0.83

Explanation:

Given the data in the question;

total number of people in the panel = 12

number of people to be selected from the panel = 2

probability you wont be selected = ?

Number of ways of selecting 2 people from the 12 member panel is;

⇒ ¹²C₂ = 12! / ( 2!( 12 - 2 )! ) = 479001600 / 7257600 = 66

so total number of outcome = 66

Now, number of ways in favor of selecting you and another person from the 12 member panel is;

⇒ ¹C₁ × ¹¹C₁ = [1! / ( 1!( 1 - 1 )! )] × [11! / ( 1!( 11 - 1 )! )] = 1 × 11 = 11

so favorable number of outcome = 11

∴ Probability of selecting you in the panel will be;

⇒ favorable number of outcome / total number of outcome

⇒ 11 / 66 = 1/6

Now, Probability of not selecting you in the panel will be;

⇒ 1 - Probability of selecting you in the panel

⇒ 1 - 1/6

0.83

Therefore, The probability that you be selected is 0.83

User Helenesh
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