Question

On one day a pet store sells 2 birds 6 gerbils 3 fish and 3 hamsters whats the data and relative frequency as a percent?

Answer 1

Birds
`F_b=14.3\%`

Gerbils
`F_g=42.9\%`

Fish
`F_f=21.4\%`

Hamsters
`F_h=21.4\%`

Explanation:

From the question we are told that:

Sales

Number of birds
`n_b=2`

Number of gerbils
`n_g=6`

Number of fish
`n_f=3`

Number of hamsters
`n_h=3`

Generally the frequency for birds
`F_b` is mathematically given b

`F_b=(n_b)/(n)*100`

`F_b=(2)/(14)*100`

`F_b=14.3\%`

Generally the frequency for Gerbils
`F_g` is mathematically given b

`F_g=(n_g)/(n)*100`

`F_g=(6)/(14)*100`

`F_g=42.9\%`

Generally the frequency for fish
`F_f` is mathematically given b

`F_f=(n_f)/(n)*100`

`F_f=(3)/(14)*100`

`F_f=21.4\%`

Generally the frequency for fish
`F_h` is mathematically given b

`F_h=(n_h)/(n)*100`

`F_h=(3)/(14)*100`

`F_h=21.4\%`