Question

On a part-time job, you are asked to bring a cylindrical iron rod of density 7800 kg/m3 , length 95.0 cm and diameter 2.00 cm from a storage room to a machinist. Calculate the weight of the rod, w. Assume the free-fall acceleration is g

Answer 1

`22.84\ \text{N}`

Step-by-step explanation:

`\rho` = Density =
`7800\ \text{kg/m}^3`

h = Length of rod = 95 cm

d = Diameter of rod = 2 cm

r = Radius =
`(d)/(2)=1\ \text{cm}`

g = Acceleration due to gravity =
`9.81\ \text{m/s}^2`

V = Volume of rod =
`\pi r^2h`

Mass is given by

`m=V\rho`

Weight is given by

`w=mg=V\rho g\\\Rightarrow w=\pi r^2h\rho g\\\Rightarrow w=\pi* (1* 10^(-2))^2* (95* 10^(-2))* 7800* 9.81\\\Rightarrow w=22.84\ \text{N}`

The weight of the rod is
`22.84\ \text{N}`.