Question

Two resistors, 2.50 Ω and 4.95 Ω, are wired in series to a 12.00 V battery. What is the equivalent resistance of the circuit?

Answer 1

7.45 Ω

Step-by-step explanation:

From the question given above, the following data were obtained:

Resistor 1 (R₁) = 2.50 Ω

Resistor 2 (R₂) = 4.95 Ω

Voltage (V) = 12 V

Equivalent Resistance (Rₑq) =?

Since the resistors are in series arrangement, the equivalent resistance can be obtained as follow:

Rₑq = R₁ + R₂

Rₑq = 2.5 + 4.95

Rₑq = 7.45 Ω

Therefore, the equivalent resistance is 7.45 Ω