Question

Calculate the molarity of a solution prepared by dissolving 6.87 grams of AgNO3 in enough water to make 2.50 liters of solution.

Answer 1

The molarity of the solution is 0.016
`(moles)/(L)`

Step-by-step explanation:

Molar concentration is a measure of the concentration of a solute in a solution.

Molarity (M) or Molar Concentration is the number of moles of solute that are dissolved in a certain volume.

Molarity is determined by dividing the moles of the solute by the volume of the solution:

`Molarity=(number of moles of solute)/(volume)`

Molarity is expressed in units
`(moles)/(liter)`.

Being 169.87 g / mole the molar mass of AgNO₃, then you can apply the following rule of three: if 169.87 grams are contained in 1 mole, 6.87 grams are contained in how many moles?

`amount of moles=(6.87 grams*1 mole)/(169.87 grams)`

amount of moles= 0.04 moles

Then:

• number of moles of solute: 0.04 moles
• volume: 2.50 L

Replacing:

`Molarity=(0.04 moles)/(2.50 L)`

Solving:

Molarity= 0.016
`(moles)/(L)`

The molarity of the solution is 0.016
`(moles)/(L)`