Question

The coordinates of the vertices of the triangle shown are A(2, 13), B(10, 5) and C(12, 14). What is the length of segment AB in units?

Answer 1

9514 1404 393

Answer:

8√2 units

Explanation:

The distance formula is useful.

d = √((x2 -x1)² +(y2 -y1)²)

d = √((10 -2)² +(5 -13)²) = √(64 +64)

d = 8√2

The length of AB is 8√2 units.