Question

a 28.7 KG sled is pulled forward with a 63 net force across the ground with MK equals 0.169 what is the acceleration of the sled

Answer 1

`0.54\ \text{m/s}^2`

Step-by-step explanation:

F = Force on the sled = 63 N

m = Mass of sled = 28.7 kg

`\mu_k` = Coefficient of kinetic friction = 0.169

g = Acceleration due to gravity =
`9.81\ \text{m/s}^2`

The force balance of the system is given by

`F-\mu_k mg=ma\\\Rightarrow a=(F-\mu_k mg)/(m)\\\Rightarrow a=(63-0.169* 28.7* 9.81)/(28.7)\\\Rightarrow a=0.54\ \text{m/s}^2`

The acceleration of the sled is
`0.54\ \text{m/s}^2`.