Answer:
0 ; -3 ; -8
Explanation:
If we look at the expression we can see that we have two fractions. If one f the denominators is equal to 0, the expression is impossible. So we have to find the values of x that make the denominators equal to 0 and exclude them.
3x^2 + 6x = 0
divide the two members for three
x^2 + 3x = 0
factorize x
x(x +3) = 0
a product is equal to 0 when at least one of the factors is equal to 0, so we have two solutions:
x = 0
x + 3 = 0 ; x= -3
0 and -3 can’t be values of x
x^2 + 11x + 24 = 0
For simplify the work we can factorise the trinomial:
We have to find two numbers whose sum is 11 and whose product is 24
the two numbers are 3 and 8, so we can rewrite the trinomal as:
(x+3)(x+8) = 0
for the consideration made above, we can find
x = -3
x = -8
so the final answer of the question is
0 ; -3 ; -8