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Graph a line with a slope of -3 that contains the point (4, -2).

(Just tell me where to put the points please)​

Graph a line with a slope of -3 that contains the point (4, -2). (Just tell me where-example-1
User Giuliopime
by
8.2k points

2 Answers

4 votes

Answer:

Explanation:

If you have both the slope and a point on the line, use the point-slope formula y - k = m(x - h), which here is y + 2 = -3(x - 4).

Now you can choose a few x values at random and calculate the associated y values. Let's try x = -1, x = 3, x = 0:

For x = -1: y + 2 = -3(-1 - 4), or y = -2 -3(-5) = -2 + 15 = 13. The point is (-1, 13).

For x = 3, we get y + 2 = -3(-1), or y = -2 + 3 = 1. The point is (3, 1).

For x = 0, y = -2 - 3(-4), or y = -2 + 12 = 10. The point is (0, 10).

Plot these three points and draw a line through them.

User Anjie
by
7.7k points
4 votes

Answer:

(4, -2), (3, 7), (5, 1), (6, -2), (7, -5)

Explanation:

These are a few of the points, so you can just connect them!

Hope this helped! :)

User Leeks And Leaks
by
7.8k points

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