Question

A 75N horizontal force is sufficient to move a 150N box on a level road at a uniform speed. What is the coefficient of friction between the box and the road?

Answer 1

`\mu_k=0.5`

Step-by-step explanation:

From the question we are told that:

Force
`F=75N`

Weight
`W=150N`

Generally the equation for coefficient of friction
`\mu_k` is mathematically given by

`\mu_k=(F)/(mg)`

`\mu_k=(75)/(150)`

`\mu_k=0.5`