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At what temperature would the volume of a gas be 0.550 L if it had a volume of 0.432 L at –20.0°C? Be careful! This is not in the correct units for temperature.

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Answer:

49.2°C is the temperature

Step-by-step explanation:

Based on Charles's law, the absolute temperature of a gas is directly proportional to the volume under constant pressure. The equation is:

V1 / T1 = V2 / T2

Where V is volume and T is absolute temperature of 1, initial state and 2, final state of the gas.

Computing the values of the problem:

V1 = 0.432L

T1 = -20.0°C + 273.15K = 253.15K

V2 = 0.550L

T2 = ?

0.432L / 253.15K = 0.550L / T2

322.3K = T2

322.3K - 273.15 =

49.2°C is the temperature

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