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How many atoms of oxygen are contained in 160 grams of N203?

User Zulfia
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1 Answer

6 votes

Answer:

3.80 × 1024 grams containing

Step-by-step explanation:

Step 1: calculate the moles of N2O3

moles= mass N2O3 /molar mass N2O3

molar mass of N2O3 = (14 x2) +( 16 x3) =76 g/mol

moles of N2O3 = 160 g/ 76 g/mol = 2.105 moles

Step 2: from the moles of N2O3 find the moles of Oxygen

=moles of N2O3 x number of oxygen atoms in N2O3( 3)

= 3 x 2.105 =6.315 moles

Step 3:use the Avogadro's law to calculate the atoms of oxygen

that is according to Avogadro's law 1 mole = 6.02 x10 ^23 atoms

6.315 moles= ? atoms

={ (6.315 moles x 6.02 x10 ^23 atoms) / 1 mole} =3.80 x10^24 atoms

User Bummi
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