Question

3.

Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.

A(n) = –3 + (n – 1)(–2.2)

A.
–2.2, –11.8, –19.8

B.
–3, –9.6, –22.8

C.
–3, –11.8, –25

D.
0, –6.6, –19.8

Answer 1

B.

–3, –9.6, –22.8

Explanation:

A(n) = a1 + (n - 1) * d

A(n) = -3 + (n - 1) * -2.2

n = term to find

a1 = first term = -3

d = common difference = -2.2

we can already see that the first term is -3 <==

4th term..

A(4) = -3 + (4 - 1) * -2.2

A(4) = -3 + 3(-2.2)

A(4) = -3 - 6.6

A(4) = - 9.6 <== 4th term

10th term...

A(10) = -3 + (10 - 1) * -2.2

A(10) = -3 + 9 * - 2.2

A(10) = -3 - 19.8

A(10) = - 22.8 <===10th term

Answer:

–3, –9.6, –22.8

Step-by-step explanation:

Given rule is:

So,

For first term:

For fourth term:

For tenth term:

The first, fourth and tenth terms are -3, -9.6 and -22.8 respectively.