Answer:
The correct answer is B :)
Explanation:
The number of k-combinations(5) from a given set S of n (24) elements
Calculating the number of combinations
Substituting our values for n= 24 and k= 5 we get
24C5 = 24!5!(24−5)!
Subtracting 5 from 24 is 19
24!5!(19)!
Expending factorial
24X23X22X21X20X19!(5X4X3X2X1)X19!
Cancelling common factors
24X23X22X21X205X4X3X2X1
Multiply numerator values and denominator values
5100480120
Divide the 5100480 by 120
Final Result :42504.0
There are 42504.0 combinations to choose 5 items out of a set of 24