9514 1404 393
Answer:
B. (4, 5π/3)
Explanation:
If you sketch the location of the point, you find the coordinates correspond to the side lengths of a 30°-60°-90° "special" triangle. The reference angle is 60°, or π/3 radians, and the magnitude of the vector is twice the short dimension, so is 2×2 = 4.
The polar coordinates are (4, 5π/3).