Question

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Sketch one cycle of y = 2 sin q.

Answer 1

Step-by-step explanation:

Just calculate some points:

θ ... y

------------------

0 ... 0

π/6 ... 2(1/2) = 1

π/3 ....2(√3/2) = √3

π/2 ... 2(1) = 2

π .... 0

3π/2 = 2(1) = 2

2π = 0