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A swimming pool is in the shape of a rectangular prism with a horizontal cross-section 10 feet by 20 feet. The pool is 5 feet deep and filled to
capacity. Water has a density of approximately 60 pounds per cubic foot, or 8 pounds per gallon.
What is the approximate weight of water in the pool?

1 Answer

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Answer:

The weight of the water in the pool is approximately 60,000 lb·f

Explanation:

The details of the swimming pool are;

The dimensions of the rectangular cross-section of the swimming pool = 10 feet × 20 feet

The depth of the pool = 5 feet

The density of the water in the pool = 60 pounds per cubic foot

From the question, we have;

The weight of the water in Pound force = W = The volume of water in the pool given in ft.³ × The density of water in the pool given in lb/ft.³ × Acceleration due to gravity, g

The volume of water in the pool = Cross-sectional area × Depth

∴ The volume of water in the pool = 10 ft. × 20 ft. × 5 ft. = 1,000 ft.³

Acceleration due to gravity, g ≈ 32.09 ft./s²

∴ W = 1,000 ft.³ × 60 lb/ft.³ × 32.09 ft./s² = 266,196.089 N

266,196.089 N ≈ 60,000 lb·f

The weight of the water in the pool ≈ 60,000 lb·f

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