Answer:
Question 1:
Louise begins factoring the polynomial, which has four terms.
8x3+24x2+10x+30
2(4x3+12x2+5x+15)
2[4x2(x+3)+5(x+3)]
Which is the completely factored form of her polynomial?
8x2(x + 3)2
2x(4x2 + 5)
2(4x2 + 5) (x + 3)
2(4x2 + 5) (x + 3)2
Answer is C
Question 2
Wen is factoring the polynomial, which has four terms.
6x3 – 12x2 + 7x – 14
6x2 (x – 2) + 7(x – 2)
Which is the completely factored form of his polynomial?
(6x2 + 7) (x –2)
(6x2 – 2) (x +7)
(6x2 + 2) (x – 7)
(6x2 – 7) (x + 2)
answer is A
Question 3
Which is the completely factored form of 3x2 – 12x – 15?
3(x + 1)(x – 5)
3(x – 1)(x + 5)
(3x + 1)(x – 15)
(3x – 1)(x + 15)
answer is A
question 4
Antonia is factoring the polynomial, which has four terms.
21x3−63x2+15x−45
3[7x3−21x2+5x−15]
3[7x2(x−3)+5(x−3)]
Which is the completely factored form of her polynomial?
21x2(x − 3)
36x2(x − 3)
3(7x2 + 5) (x − 3)
3(12x2 + 5) (x − 3)
answer is C
question 5
What is the greatest common factor of the terms in the polynomial 4x4 – 32x3 – 60x2?
4
4x
4x2
4x3
answer is C
question 6
Which product of prime polynomials is equivalent to 8x4 + 36x3 – 72x2?
4x(2x – 3)(x2 + 6)
4x2(2x – 3)(x + 6)
2x(2x – 3)(2x2 + 6)
2x(2x + 3)(x2 – 6)
answer is B
question 7
Which product of prime polynomials is equivalent to 36x3 – 15x2 – 6x?
x(3x – 2)(4x + 1)
3x(3x – 2)(4x + 1)
3(x2 + 1)(4x – 1)
3(x2 + 1)(4x + 1)
answer is B
question 8
Pascha is factoring the polynomial, which has four terms.
3x3 – 15x2 + 8x – 40
3x2(x – 5) + 8(x – 5)
Which is the completely factored form of her polynomial?
(3x2 – 5) (x + 8)
(3x2 – 8) (x + 5)
(3x2 + 8) (x – 5)
(3x2 + 5) (x – 8)
answer B
question 9
Which product of prime polynomials is equivalent to 3x4 – 81x?
3x(x – 3)(x2 – 3x – 9)
3x(x – 3)(x2 + 3x + 9)
3x(x – 3)(x – 3)(x + 3)
3x(x – 3)(x + 3)(x + 3)
answer B
question 10
Which product of prime polynomials is equivalent to 8x3 – 2x?
x(2x – 1)(2x – 1)
2x(x + 1)(x – 1)
2x2(2x + 1)(2x – 1)
2x(2x + 1)(2x – 1)
Answer D