Question

Determine the equation of the circle graphed below.

Answer 1

Explanation:

hello :

hello:

note : an equatin for the circle is : (x-a)²+(y-b)²=r²

when the center is the point : C(a , b) and the radius r

use this graph : given two points in this circle A(-3,1) and B(-7,1)

1) AB/2 = r = 4/2 = 2

2) the midipoint for the segment AB is the center C

a = (-3-7)/2 and b = (1+1)/2

a= -5 and b= 1 so : C(-5 , 1)

an equation is : (x+5)²+(y-1)²=2²

Answer 2

(x + 5)² + (y - 1)² = 4

Explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Here (h, k ) = (- 5, 1) and r = 2, then

(x - (- 5))² + (y - 1)² = 2² , that is

(x + 5)² + (y - 1)² = 4