Question

A child is flying a kite. If the string is pulled tight to its full length of 40 feet and is held at an angle of 71 degrees above the ground, how high is the kite? Round your answer to the nearest whole foot.

Answer 1

38feet high

Explanation:

Given the following

Length of the string = 40feet (hypotenuse)

Angle of elevation = 71 degrees

Required

Height of the kite (opposite)

Using the SOH CAH TOA identity

Sin theta = opp/hyp

Sin 71 = H/40

H = 40sin 71

H = 40(0.9455)

H = 37.82

Hence the kite is 38feet high (to the nearest whole number)