Question

The nth term of the GP is (-1)^n(2)^n.


`( - 1)^(n) (2)^(n)`

Find the first three terms.​

Answer 1

-2, 4 and -8

Step-by-step explanation:

Given the nth term of a GP expressed as;

`a_n = (-1)^n(2)^n`

When n = 1

`a_1 = (-1)^1(2)^1\\a_1 = -1 * 2\\a_1 = -2\\`

when n = 2

`a_2 = (-1)^2(2)^2\\a_2 = 1 * 4\\a_2 = 4\\`

when n = 3

`a_3 = (-1)^3(2)^3\\a_3 = -1 * 8\\a_3 = -8\\`

Hence the first three terms of the sequence are -2, 4 and -8