Question

2NH3(g)+3CuO(s)= + 3H2O(I)+N2(g)

If a sample of 51.0g of ammonia's reacted with excess copper oxide, how many moles of nitrogen would be produced?

Answer 1

1.50 mol N₂

Step-by-step explanation:

Step 1: Write the balanced equation

2 NH₃(g) + 3 CuO(s) ⇒ 3 Cu + 3 H₂O(I) + N₂(g)

Step 2: Calculate the moles corresponding to 51.0 g of NH₃

The molar mass of NH₃ is 17.03 g/mol.

51.0 g × 1 mol/17.03 g = 2.99 mol

Step 3: Calculate the moles of N₂ produced from 2.99 moles of NH₃

The molar ratio of NH₃ to N₂is 2:1. The moles of N₂ produced are:

2.99 mol NH₃ × 1 mol N₂/2 mol NH₃ = 1.50 mol N₂